Matrix Multiplication Calculator

This Matrix Multiplication Calculator helps you multiply two matrices and shows each step clearly. In Algebra 2, matrix multiplication is used when working with matrices, systems, transformations, and organized numerical data. It works by taking a row from the first matrix and a column from the second matrix, multiplying corresponding entries, and adding the results to form each entry of the product matrix.

Step-by-step method

1. Check that the number of columns in Matrix A equals the number of rows in Matrix B.
2. Multiply each row of Matrix A by each column of Matrix B.
3. Add the products and place each result in the matching position of the product matrix.

Formula:

Example 1: Take the values below.

Step 1 - Check that the number of columns in Matrix A equals the number of rows in Matrix B.

In this problem: Matrix A is \(2 \times 2\) and Matrix B is \(2 \times 2\). Since \(2 = 2\), multiplication is possible. The product matrix will be \(2 \times 2\).

Step 2 - Multiply each row of Matrix A by each column of Matrix B.

In this problem: Each entry is made by multiplying one row of Matrix A with one column of Matrix B.

Step 3 - Add the products and place each result in the matching position of the product matrix.

In this problem: After multiplying, add the products and place each result in the product matrix.

Final answer:

Example 2: Take the values below.

Step 1 - Check that the number of columns in Matrix A equals the number of rows in Matrix B.

In this problem: Matrix A is \(2 \times 3\) and Matrix B is \(3 \times 2\). Since \(3 = 3\), multiplication is possible. The product matrix will be \(2 \times 2\).

Step 2 - Multiply each row of Matrix A by each column of Matrix B.

In this problem: Each entry is made by multiplying one row of Matrix A with one column of Matrix B.

Step 3 - Add the products and place each result in the matching position of the product matrix.

In this problem: After multiplying, add the products and place each result in the product matrix.

Final answer:

See Example 1 Hide Example 1

Problem

\(\begin{pmatrix} 1 & 2 \\ 3 & 4 \end{pmatrix} \times \begin{pmatrix} 5 & 6 \\ 7 & 8 \end{pmatrix}\)

Approach

Step-by-step method

1. Check that the number of columns in Matrix A equals the number of rows in Matrix B.
2. Multiply each row of Matrix A by each column of Matrix B.
3. Add the products and place each result in the matching position of the product matrix.

Step 1

Step 1 - Check that the number of columns in Matrix A equals the number of rows in Matrix B.

In this problem: Matrix A is \(2 \times 2\) and Matrix B is \(2 \times 2\). Since \(2 = 2\), multiplication is possible. The product matrix will be \(2 \times 2\).

\(\begin{pmatrix} 1 & 2 \\ 3 & 4 \end{pmatrix} \times \begin{pmatrix} 5 & 6 \\ 7 & 8 \end{pmatrix}\)

Step 2

Step 2 - Multiply each row of Matrix A by each column of Matrix B.

In this problem: Each entry is made by multiplying one row of Matrix A with one column of Matrix B.

\(\begin{pmatrix} 1 \cdot 5 + 2 \cdot 7 & 1 \cdot 6 + 2 \cdot 8 \\ 3 \cdot 5 + 4 \cdot 7 & 3 \cdot 6 + 4 \cdot 8 \end{pmatrix}\)

Step 3

Step 3 - Add the products and place each result in the matching position of the product matrix.

In this problem: After multiplying, add the products and place each result in the product matrix.

\(\begin{pmatrix} 5 + 14 = 19 & 6 + 16 = 22 \\ 15 + 28 = 43 & 18 + 32 = 50 \end{pmatrix} = \begin{pmatrix} 19 & 22 \\ 43 & 50 \end{pmatrix}\)

Final Answer

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See Example 2 Hide Example 2

Problem

\(\begin{pmatrix} 2 & 0 & -1 \\ 3 & 1 & 4 \end{pmatrix} \times \begin{pmatrix} 1 & 2 \\ 0 & 5 \\ -2 & 3 \end{pmatrix}\)

Approach

Step-by-step method

1. Check that the number of columns in Matrix A equals the number of rows in Matrix B.
2. Multiply each row of Matrix A by each column of Matrix B.
3. Add the products and place each result in the matching position of the product matrix.

Step 1

Step 1 - Check that the number of columns in Matrix A equals the number of rows in Matrix B.

In this problem: Matrix A is \(2 \times 3\) and Matrix B is \(3 \times 2\). Since \(3 = 3\), multiplication is possible. The product matrix will be \(2 \times 2\).

\(\begin{pmatrix} 2 & 0 & -1 \\ 3 & 1 & 4 \end{pmatrix} \times \begin{pmatrix} 1 & 2 \\ 0 & 5 \\ -2 & 3 \end{pmatrix}\)

Step 2

Step 2 - Multiply each row of Matrix A by each column of Matrix B.

In this problem: Each entry is made by multiplying one row of Matrix A with one column of Matrix B.

\(\begin{pmatrix} 2 \cdot 1 + 0 \cdot 0 + (-1) \cdot (-2) & 2 \cdot 2 + 0 \cdot 5 + (-1) \cdot 3 \\ 3 \cdot 1 + 1 \cdot 0 + 4 \cdot (-2) & 3 \cdot 2 + 1 \cdot 5 + 4 \cdot 3 \end{pmatrix}\)

Step 3

Step 3 - Add the products and place each result in the matching position of the product matrix.

In this problem: After multiplying, add the products and place each result in the product matrix.

\(\begin{pmatrix} 2 + 0 + 2 = 4 & 4 + 0 + -3 = 1 \\ 3 + 0 + -8 = -5 & 6 + 5 + 12 = 23 \end{pmatrix} = \begin{pmatrix} 4 & 1 \\ -5 & 23 \end{pmatrix}\)

Final Answer

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