Division of Large Numbers Calculator
This calculator divides two numbers of any size and shows the working using long division. You’ll get a quotient (the answer) and a remainder (what’s left).
Step-by-step method
- Step 1 (Set up): Set up the long-division box: the divisor goes outside, the dividend goes inside, and the quotient will be written on top.
- Step 2 (Repeat the long-division cycle): Start with the first digit on the left of the dividend. If the divisor does not fit, include the next digit (and keep including digits) until you have a number big enough to divide. Ask: How many times does the divisor fit into that number? Write that digit in the quotient above the last digit you used (if it does not fit after you have started, write 0 in the quotient for that position). Multiply (divisor × that digit) and write it underneath, subtract to get a remainder, then bring down the next digit and repeat until there are no digits left. The number on top is the quotient, and the final leftover is the remainder.
Example 1: 84 ÷ 7
Step 1 (Set up) - Set up the long-division box: the divisor goes outside, the dividend goes inside, and the quotient will be written on top.
In this problem: We divide 84 by 7. The quotient goes on top, and we work from left to right.
| 7 | 8 | 4 |
Step 2 (Repeat the long-division cycle) - Start with the first digit on the left of the dividend. If the divisor does not fit, include the next digit (and keep including digits) until you have a number big enough to divide. Ask: How many times does the divisor fit into that number? Write that digit in the quotient above the last digit you used (if it does not fit after you have started, write 0 in the quotient for that position). Multiply (divisor × that digit) and write it underneath, subtract to get a remainder, then bring down the next digit and repeat until there are no digits left. The number on top is the quotient, and the final leftover is the remainder.
In this problem: We start with the first digit 8 because it is big enough to divide by 7. Then we repeat: divide, multiply, subtract, bring down.
| 7 | 8 | 4 |
Step 2a (Work) - Work with 8.
In this problem: We look at 8. 7 fits 1 time. Multiply: 7 × 1 = 7. Subtract: 8 − 7 = 1.
| 1 | ||
| 7 | 8 | 4 |
| - | 7 | |
| 1 |
Step 2b (Bring down) - Bring down the next digit.
In this problem: We bring down the next digit 4 next to the remainder 1. Now we have 14 to work with.
| 1 | ||
| 7 | 8 | 4 |
| - | 7 | |
| 1 | 4 |
Step 2c (Work) - Work with 14.
In this problem: We look at 14. 7 fits 2 times. Multiply: 7 × 2 = 14. Subtract: 14 − 14 = 0.
| 1 | 2 | |
| 7 | 8 | 4 |
| - | 7 | |
| 1 | 4 | |
| - | 1 | 4 |
| 0 |
Final answer: 84 ÷ 7 = 12 R 0
Example 2: 1000 ÷ 8
Step 1 (Set up) - Set up the long-division box: the divisor goes outside, the dividend goes inside, and the quotient will be written on top.
In this problem: We divide 1000 by 8. The quotient goes on top, and we work from left to right.
| 8 | 1 | 0 | 0 | 0 |
Step 2 (Repeat the long-division cycle) - Start with the first digit on the left of the dividend. If the divisor does not fit, include the next digit (and keep including digits) until you have a number big enough to divide. Ask: How many times does the divisor fit into that number? Write that digit in the quotient above the last digit you used (if it does not fit after you have started, write 0 in the quotient for that position). Multiply (divisor × that digit) and write it underneath, subtract to get a remainder, then bring down the next digit and repeat until there are no digits left. The number on top is the quotient, and the final leftover is the remainder.
In this problem: We start with the first digit 1. Since 8 does not fit into 1, we include more digits from the left to make 10. Then we repeat: divide, multiply, subtract, bring down.
| 8 | 1 | 0 | 0 | 0 |
Step 2a (Check) - Check 1.
In this problem: We look at 1. 8 does not fit yet, so we include the next digit 0 to make 10.
| 8 | 1 | 0 | 0 | 0 |
Step 2b (Work) - Work with 10.
In this problem: We look at 10. 8 fits 1 time. Multiply: 8 × 1 = 8. Subtract: 10 − 8 = 2.
| 1 | ||||
| 8 | 1 | 0 | 0 | 0 |
| - | 8 | |||
| 2 |
Step 2c (Bring down) - Bring down the next digit.
In this problem: We bring down the next digit 0 next to the remainder 2. Now we have 20 to work with.
| 1 | ||||
| 8 | 1 | 0 | 0 | 0 |
| - | 8 | |||
| 2 | 0 |
Step 2d (Work) - Work with 20.
In this problem: We look at 20. 8 fits 2 times. Multiply: 8 × 2 = 16. Subtract: 20 − 16 = 4.
| 1 | 2 | |||
| 8 | 1 | 0 | 0 | 0 |
| - | 8 | |||
| 2 | 0 | |||
| - | 1 | 6 | ||
| 4 |
Step 2e (Bring down) - Bring down the next digit.
In this problem: We bring down the next digit 0 next to the remainder 4. Now we have 40 to work with.
| 1 | 2 | |||
| 8 | 1 | 0 | 0 | 0 |
| - | 8 | |||
| 2 | 0 | |||
| - | 1 | 6 | ||
| 4 | 0 |
Step 2f (Work) - Work with 40.
In this problem: We look at 40. 8 fits 5 times. Multiply: 8 × 5 = 40. Subtract: 40 − 40 = 0.
| 1 | 2 | 5 | ||
| 8 | 1 | 0 | 0 | 0 |
| - | 8 | |||
| 2 | 0 | |||
| - | 1 | 6 | ||
| 4 | 0 | |||
| - | 4 | 0 | ||
| 0 |
Final answer: 1000 ÷ 8 = 125 R 0
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